Q. 125.0( 1 Vote )

A vector <span la

Answer :

Let l, m, n be the direction cosines of the vector r

Vector r is inclined at equal angles to the three axes.


l = cosα, m = cos α, n = cosα


l = m = n.


Also, we know that -


l2 + m2 + n2 = 1


cos2α + cos2α + cos2α = 1


3 cos2α = 1



Hence, the direction cosines of the vector which are equally inclined to the axes are


r = |r |( l î + m ĵ + n k̂)



(Given, |r | = 2√ 3 )


r = ±(2 î + 2ĵ + 2 k̂)


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