Given A = (–1, 3) and B = (–2, 1)
We know position vector of a point (x, y) is given by, where and are unit vectors in X and Y directions.
Let position vectors of points A and B be and respectively.
We also have.
Recall the vector is given by
Now, it is given that there exists a point say (x, y) whose position vector is same as.
We know position vector of a point (x, y) is given by.
By comparing both the sides, we get x = –1 and y = –2
Thus, (–1, –2) is the tip of position vector that is same as .
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