The general equation of a conic is as follows
ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 where a, b, c, f, g, h are constants
For a circle, a = b and h = 0.
The equation becomes:
x2 + y2 + 2gx + 2fy + c = 0…(i)
Given, x2 + y2 + x - y = 0
Comparing with (i) we see that the equation represents a circle with 2g = 1 , 2f = - 1 and c = 0.
Centre ( - g, - f) =
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