Q. 17

# Show that the quadrilateral formed by the straight lines x – y = 0, 3x + 2y = 5, x – y = 10 and 2x + 3y = 0 is cyclic and hence find the equation of the circle.

Solving the euations we get the coordinates of the quadrilateral.

Slope of = 1

Slope of CD = 1

AB||CD

Slope of BD = AC = - 1

AC||BD

So they form a rectangle with all sides = 90

The quadrilateral is cyclic as sum of opposite angles = 180.

Now, AD = diameter of the circle equation of the circle with extremities A(0, 0)&D(6, - 4) is

(x - 0)(x - 6) + (y - 0)(y + 4) = 0

x2 + y2 – 6x + 4y = 0

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