Q. 14.0( 5 Votes )

Show that the equ

Answer :

The general equation of a conic is as follows


ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 where a, b, c, f, g, h are constants


For a circle, a = b and h = 0.


The equation becomes:


x2 + y2 + 2gx + 2fy + c = 0…(i)


Given, x2 + y2 – 4x + 6y – 5 = 0


Comparing with (i) we see that the equation represents a circle with 2g = - 4 g = - 2, 2f = 6f = 3 and c = - 5.


Centre ( - g, - f) = { - ( - 2), - 3}


= (2, - 3).


Radius =




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