Q. 13 A4.3( 8 Votes )

Find the equation

The equation of a circle passing through the coordinates of the end points of diameters is:

(x - x1) (x - x2) + (y - y1)(y - y2) = 0

Substituting, values:(x1, y1) = (3, 2) & (x2, y2) = (2, 5)

We get:

(x - 3)(x - 2) + (y - 2)(y - 5) = 0

x2 - 2x - 3x + 6 + y2 - 5y - 2y + 10 = 0

x2 + y2 - 5x - 7y + 16 = 0

Ans: x2 + y2 - 5x - 7y + 16 = 0

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