# Using integration

Here we have to find the area of the triangle whose triangle are A(2,1), B(3,4) and C(5,2) as shown below.

The equation of AB,

Y = 3x – 5 ...(i)

The equation of BC,

...(ii)

The equation of AC,

Now the required area (A) =

[(Area between line AB and x - axis) - (Area between line AC and x - axis) from x = 2 to x = 3]

+ [(Area between line BC and x - axis) - (Area between line AC and x - axis) from x = 3 to x = 5]

The area of the region bounded by the triangle whose vertices are (2,1), (3,4) and (5,2) is 4 sq. units

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