# Find the area, lying above x - axis and included between the circle circle x2 + y2 = 8x and the parabola y2 = 4x.

To find area lying above x - axis and included in the circle

x2 + y2 = 8x ...(i)

Or (x – 4)2 + y2 = 16

And ...(ii)

On solving the equation (i) and (ii),

x2 + y2 = 8x

Or x2 – 4x = 0

Or x(x – 4) = 0

Or x = 0 and x = 4

When x = 0, y = 0

When x = 4, y = ±4

Equation (i) represents a circle with centre (4,0) and meets axes at (0,0) and (8,0).

Equation (ii) represent a parabola with vertex (0,0) and axis as x - axis.

They intersect at (4, – 4) and (4,4).

These are shown in the graph below: - Required area = Region OABO

Required area = Region ODBO + Region DABD …(1)

Region ODBO  Region OBDO = 32/3 sq. units …(2)

Region DABD   Region DABD = 4π sq. units …(3)

Using (1),(2) and (3), We get

Required area = = 4 sq. units

The area lying above the x - axis and included between the circle x2 + y2 = 8x and the parabola y2 = 4x is 4 sq. Units

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