# A spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls. If the diameters of two balls be cm and 2 cm, find the diameter of the third ball.

Volume of a sphere = (4/3)πr3

Total volume remains same during recasting.

Given, spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls and the diameters of two balls are cm and 2 cm.

Let the diameter of the third ball be ‘a’ cm.

27/8 = (27/64) + 1 + (a3/8)

a3/8 = 125/64

a3 = 125/8

a = 5/2 cm

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