Q. 73.7( 3 Votes )

# A spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls. If the diameters of two balls be cm and 2 cm, find the diameter of the third ball.

Answer :

Volume of a sphere = (4/3)πr^{3}

Total volume remains same during recasting.

Given, spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls and the diameters of two balls are cm and 2 cm.

Let the diameter of the third ball be ‘a’ cm.

⇒ 27/8 = (27/64) + 1 + (a^{3}/8)

⇒ a^{3}/8 = 125/64

⇒ a^{3} = 125/8

⇒ a = 5/2 cm

Rate this question :

A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii of two of these balls are 1.5 cm and 2 cm. The radius of the third ball is

RS Aggarwal & V Aggarwal - MathematicsA sphere and a cube are of the same height. The ratio of their volumes is

RD Sharma - MathematicsIf a solid sphere of radius 10 cm is moulded into 8 spherical solid balls of equal radius, then the surface area of each ball (in sq. cm) is

RD Sharma - MathematicsThe ratio between the volume of a sphere and volume of a circumscribing right circular cylinder is

RD Sharma - MathematicsIf the surface area of a sphere is 144πm^{2}, then its volume (in m^{3}) is