Q. 73.7( 3 Votes )

A spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls. If the diameters of two balls be cm and 2 cm, find the diameter of the third ball.

Answer :

Volume of a sphere = (4/3)πr3


Total volume remains same during recasting.


Given, spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls and the diameters of two balls are cm and 2 cm.


Let the diameter of the third ball be ‘a’ cm.



27/8 = (27/64) + 1 + (a3/8)


a3/8 = 125/64


a3 = 125/8


a = 5/2 cm


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