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Volume of a sphere = (4/3)πr3

Volume of a cylinder = πr2h

Given, a cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm.

Volume of water displaced = Volume of the iron ball

r3 = 1728

r = 12 cm

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