Q. 143.7( 3 Votes )
A cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm. Find the radius of the ball. (Use π =22/7).
Volume of a sphere = (4/3)πr3
Volume of a cylinder = πr2h
Given, a cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm.
Volume of water displaced = Volume of the iron ball
⇒ r3 = 1728
⇒ r = 12 cm
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