# A cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm. Find the radius of the ball. (Use π =22/7).

Volume of a sphere = (4/3)πr3

Volume of a cylinder = πr2h

Given, a cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm.

Volume of water displaced = Volume of the iron ball

r3 = 1728

r = 12 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area of Right Circular Cylinder52 mins
Surface Area and Volume of Spheres40 mins
Surface Area of Right Circular Cylinder49 mins
Surface Area of Cube and Cuboid49 mins
Surface Area and Volume of Cone24 mins
10 Important Questions of Surface Area and Volume51 mins
Surface Area and Volume of Right Circular Cylinders42 mins
Surface Area and Volume of Right Circular Cone37 mins
Quiz | Mensuration42 mins
Quiz | Surface Area & Volumes49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses