Q. 8 D4.7( 3 Votes )

Find the sum of t

Answer :

Generalized term be (2r - 1)2=4r2 + 1 - 4r

1st term = 4(1)2 + 1 - 4(1)


2nd term =4(2)2 + 1 - 4(2)


And so on


nth term= 4n2 + 1 - 4n


Summation=1st term + 2nd term + …….. + nth term


= 4(1)2 + 1 - 4(1) + 4(2)2 + 1 - 4(2) ………4n2 + 1 - 4n ……(1)


We know ,



Thus


From (1) we have


Summation =


We know by property that:


∑axn + bxn - 1 + cxn - 2…….d0=a∑xn + b∑xn - 1 + c∑xn - 2…….. + d0∑1


Thus


(2)


We know







Thus substituting above values in (2)







Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A person has 2 paRD Sharma - Mathematics

The sum of the seRD Sharma - Mathematics

How many terms ofRD Sharma - Mathematics

If <span lang="ENRD Sharma - Mathematics

Let anRD Sharma - Mathematics

Find the sum of 2RD Sharma - Mathematics

If <span lang="ENRS Aggarwal - Mathematics

Find the sum (41 RS Aggarwal - Mathematics

Find the sum (2 +RS Aggarwal - Mathematics

If<span lang="EN-RS Aggarwal - Mathematics