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# Divide the first polynomial by the second. Explain the steps.

–8y^{5}; –y^{3}

Answer :

The division is as follows:

Here when –y^{3} is multiplied by 8y^{2} we get -8y^{5} as the result.

Here the divisor is negative and the dividend is also negative so the quotient has to be positive to get remainder zero.

In division the sign of the product [divisor × quotient] is always inverted to get the final result.

So the sign of product should always be opposite to that of the dividend.

So -8y^{5} becomes perfectly divisible by –y^{3}and hence the quotient is 8y^{2} and remainder is 0.

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