# A vertex of a square is at the origin and its one side lies along the line 3x – 4y – 10 = 0.Find the area of the square.

Given: ABCD is a square and equation of BC is 3x – 4y – 10 = 0

To find : Area of the square

Formula used:

We know that the length of perpendicular from (m,n) to the line ax + by + c = 0 is given by,

D

The given equation of the line is 3x – 4y – 10 = 0

Here m= 0 and n= 0 , a = 3 , b = -4 , c = -10

D

D

D

Side of the square=D=2

Area of the square = 22 = 4 square units

Area of the square = 4 square units

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