# Find the equation of the line passing through the point (0, 3) and perpendicular to the line x – 2y + 5 = 0 Given: The given line is x - 2y + 5 = 0. The line perpendicular to this given line passes through (0,3)

Formula to be used: The product of slopes of two perpendicular lines = - 1.

The slope of this line is 1/2 . the slope of the perpendicular line = The equation of the line can be written in the form y = ( - 2)x + c

(c is the y - intercept)

This line passes through (0,3) so the point will satisfy the equation of the line. 3 = ( - 2)x0 + c i.e. c = 3

The required equation is y = - 2x + 3

i.e. 2x + y = 3

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