Q. 83.8( 6 Votes )

Find the equation of the line passing through the point (0, 3) and perpendicular to the line x – 2y + 5 = 0

Answer :


Given: The given line is x - 2y + 5 = 0. The line perpendicular to this given line passes through (0,3)


Formula to be used: The product of slopes of two perpendicular lines = - 1.


The slope of this line is 1/2 .


the slope of the perpendicular line =


The equation of the line can be written in the form y = ( - 2)x + c


(c is the y - intercept)


This line passes through (0,3) so the point will satisfy the equation of the line.


3 = ( - 2)x0 + c i.e. c = 3


The required equation is y = - 2x + 3


i.e. 2x + y = 3


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