Q. 144.1( 8 Votes )
Find the equation of the line passing through ( - 3, 5) and perpendicular to the line through the points (2, 5) and ( - 3, 6).
Answer :
Given: The line perpendicular to the line passing through (2,5) and ( - 3,6) passes through ( - 3,5).
Formula to be used: If (a,b) and (c,d) are two points then the equation of the line passing through them is 
Product of slopes of two perpendicular lines = - 1
The equation of the line joining points (2,5) and ( - 3,6) is
Or, 5y - 25 = - x + 2
i.e. the given line is x + 5y = 27.
The slope of this line is 
.
the slope of the perpendicular line = 
The equation of the line can be written in the form y = 5x + c.
(c is the y - intercept)
This line passes through ( - 3,5).
Hence, 5 = 5x( - 3) + c or, c = 20
The required equation of the line will be y = 5x + 20
i.e. 5x - y + 20 = 0
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