# Find the equation of the line whose(i) slope = 3 and y - intercept = 5(ii) slope = - 1 and y - intercept = 4(iii) slope = and y - intercept = - 3

(i) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.

Here, m = 3 and c = 5.

Hence, y = (3)x + (5)

i.e. y = 3x + 5

(ii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.

Here, m = - 1 and c = 4.

Hence, y = ( - 1)x + (4)

i.e. x + y = 4

(iii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.

Here, m = and c = - 3.

Hence, y = ()x + ( - 3)

Or, 5y = - 2x - 3 i.e. 2x + 5y + 3 = 0

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