1 2 3 4 5 6 7 8 A 8 B 8 C 9 10 11 12 13 14 15 A 15 B 15 C 15 D 16 17 18 19 20 21 22 23 24

RS Aggarwal - Mathematics

20. Straight Lines

Exercise 20A

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23

Exercise 20B

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25

Exercise 20C

1 2 3 4 5 6 7 8 A 8 B 8 C 9 10 11 12 13 14 15 A 15 B 15 C 15 D 16 17 18 19 20 21 22 23 24

Exercise 20D

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Exercise 20E

1 2 3 4 5 6 7 8 9 10

Exercise 20F

1 A 1 B 1 C 1 D 1 E 1 F 2 3

Exercise 20G

1 2 3 4 5 6 7 8 9

Exercise 20H

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19

Exercise 20I

1 2 3 4 5 6 7 8 9 10 11

Exercise 20J

1 2 3 4 5 6 7 8 9 10

Exercise 20K

1 2 3 4 5 6 7 8 9 10

Q. 15 C5.0( 1 Vote )

<span lang="EN-US

Class 11th RS Aggarwal - Mathematics 20. Straight Lines

Answer :

The slope of the equation can be calculated using

Now using two point form of the equation of a line

3x - 15 - 5y + 15 = 0

3x - 5y = 0

So, required equation of line is 3x - 5y = 0.

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