# The vertices of a

The vertices of the given quadrilateral are A(-4,-2) B(2, 6), C(8, 5) and D(9, -7)

The mid point of a line A(x1,y1) and B(x2,y2) is found out by

Now midpoint of AB =

The midpoint of BC =

The midpoint of CD =

Midpoint of DA =

So now we have four points

P(-1,2),Q(5,5.5),R(8.5,-1),S(2.5,-4.5)

Slope of PQ =

Slope of QR =

Slope of RS =

Slope of SP =

Now we can observe that slope of PQ = RS and slope of QR = SP

Which shows that line PQ is parallel to RS and line QR is parallel to SP

Also, the product of two adjacent lines is not equal to -1

Therefore PQRS is a parallelogram.

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