Q. 95.0( 1 Vote )

# Evaluate the foll

Answer : Formula used: where, Here, a = 1 and b = 2

Therefore,  Let, Here, f(x) = x2 and a = 1 Now, by putting x = 1 in f(x) we get,

f(1) = 12 = 1

f(1 + h)

= (1 + h)2

= h2 + 12 + 2(h)(1)

= h2 + 1 + 2(h)

Similarly, f(1 + 2h)

= (1 + 2h)2

= (2h)2 + 12 + 2(2h)(1)

= (2h)2 + 1 + 2(2h)

{ (x + y)2 = x2 + y2 + 2xy}  In this series, 1 is getting added n times Now take h2 and 2h common in remaining series   Put, Since,              Rate this question :

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