Q. 305.0( 1 Vote )

# Evaluate the foll Formula used: where, Here, a = 1 and b = 3

Therefore,  Let, Here, f(x) = x2 + x and a = 1 Now, by putting x = 1 in f(x) we get,

f(1) = 12 + 1 = 1 + 1 = 2

f(1 + h)

= (1 + h)2 + (1 + h)

= h2 + 12 + 2(h)(1) + 1 + h

= h2 + 2h + h + 1 + 1

= h2 + 3h + 2

Similarly, f(1 + 2h)

= (1 + 2h)2 + (1 + 2h)

= (2h)2 + 12 + 2(2h)(1) + 1 + 2h

= (2h)2 + 4h + 2h + 1 + 1

= (2h)2 + 6h + 2

{ (x + y)2 = x2 + y2 + 2xy}  In this series, 2 is getting added n times Now take h2 and 3h common in remaining series   Put, Since,              Rate this question :

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