Q. 205.0( 1 Vote )

# Evaluate the foll Formula used: where, Here, a = 1 and b = 4

Therefore,  Let, Here, f(x) = 3x2 + 2x and a = 1 Now, by putting x = 1 in f(x) we get,

f(1) = 3(1)2 + 2(1) = 3 + 2 = 5

f(1 + h)

= 3(1 + h)2 + 2(1 + h)

= 3{h2 + 12 + 2(h)(1)} + 2 + 2h

= 3h2 + 3 + 6h + 2 + 2h

= 3h2 + 8h + 5

Similarly, f(1 + 2h)

= 3(1 + 2h)2 + 2(1 + 2h)

= 3{(2h)2 + 12 + 2(2h)(1)} + 2 + 4h

= 3(2h)2 + 3 + 6(2h) + 2 + 2(2h)

= 3(2h)2 + 8(2h) + 5

{ (x + y)2 = x2 + y2 + 2xy}  Since 5 is repeating n times in series Now take 3h2 and 8h common in remaining series   Put, Since,             Rate this question :

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