Answer :

a, b, c, d are in G.P.


Therefore,


bc = ad … (1)


b2 = ac … (2)


c2 = bd … (3)


LHS = b2 + bd + bc + cd


LHS = ac + bd + bc + cd {on substituting value of b2 } …(1)


RHS = c2 + cd + ac + ad


RHS = bd + cd + ac + bc {putting value of c2} …(2)


From equation 1 and 2 we can say that –


LHS = RHS Hence proved


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