Q. 84.3( 4 Votes )

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Answer :

let us assume


let x = tany


differentiating both sides


dx = sec2 y dy


for x = ∞



For x = 0


0 = y


thus




(since sec2y – tan2y = 1)


.....equation 1


By property, we know that



….....equation 2


Adding equations 1 and 2, we get,



We know




since logm + logn = logmn


since tany = 1/coty


since log 1 = 0


Thus


2I = 0


I = 0


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