Answer :

As a, b, c are in G.P.


Therefore


b2 = ac … (1)


We have to prove a3, b3, c3 are in GP or


we need to prove: (b3)2 = (a3c3) {using idea of GM}


On cubing equation 1 we get,


b6 = a3c3


(b3)2 = (a3c3)


Hence a3,b3,c3 are in GP.


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