Answer :
As a, b, c are in G.P.
Therefore
b2 = ac … (1)
We have to prove a3, b3, c3 are in GP or
we need to prove: (b3)2 = (a3c3) {using idea of GM}
On cubing equation 1 we get,
⇒ b6 = a3c3
⇒ (b3)2 = (a3c3)
Hence a3,b3,c3 are in GP.
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