Answer :
Let a be the first term, and r be the common ratio.
According to the question-
a + ar + ar2 + …∞ = S
⇒ S = a(1+r+r2+…∞)
We observe that the above progression possess a common ratio. So it is a geometric progression.
Common ratio = r and first term (a) = 1
Sum of infinite GP = ,where a is the first term and k is the common ratio.
Note: We can only use the above formula if |k|<1
∴ S = …equation 1
Also, as per the question
S1 = a2 + a2r2 + a2r4 + …∞
⇒ S1 = a2 (1+r2+r4+…∞)
We observe that above progression possess a common ratio. So it is a geometric progression.
Common ratio = r2 and first term (a) = 1
Sum of infinite GP = ,where a is the first term and k is the common ratio.
Note: We can only use the above formula if |k|<1
∴ S1 =
⇒ S1 =
From equation 1,we have-
⇒ S1 = ….equation 2
Dividing equation 1 by 2, we get-
⇒
⇒ (1-r)S2 = (1+r)S1
⇒ S2 – S1 = r(S2 + S1)
∴ r =
Put the value of r in equation 1 to get a.
a =
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