# The common ratio

Given: Common Ratio = 3

Sum of GP = 728

Sum of GP for n terms =

Last term say it be n

Tn = arn - 1

486 = a3n - 1

1458 = a.3n …(1)

1456 = a.3n - a…(2)

Subtracting 1 from 2 we get

1458 - 1456 = a.3n - a.3n + a

a = 2.

The first term is 2.

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