Answer :
The given expression can also be written as
⇒ …(1)
⇒
Now this term is in GP.
2, 4, 8…to n terms
∴ Common Ratio =
∴ Sum of GP for n terms = …(2)
⇒ a = 2, r = 2, n = n
∴ Substituting the above values in (2) we get,
⇒
⇒ 2n + 1 – 2.
⇒
Now this term is in GP.
1, 3, 9…to n terms
∴ Common Ratio = r =
∴ Sum of GP for n terms = …(2)
⇒ a = 1, r = 3, n = n
∴ Substituting the above values in (2) we get,
⇒
⇒
Now, Adding both these we will get the required solution.
⇒ 2n + 1 – 2 +
⇒
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