Q. 23.9( 7 Votes )

# Find the area enclosed by each of the following figures [fig. 20.49 (i)-(ii)] as the sum of the areas of a rectangle and a trapezium.

Answer :

**Figure (i)**

Area of given figure = Area of trapezium + area of rectangle

Area of given figure =

Area of given figure =

Area of given figure =

Therefore area of given figure is 424 cm^{2}

**Figure (ii)**

Area of given figure = Area of trapezium + area of rectangle

Area of given figure =

Area of given figure =

Area of given figure =

Therefore area of given figure is 384 cm^{2}

**Figure (iii)**

Using pythagorous theorem in the right angled triangle

5^{2} = 4^{2} + x^{2}

x^{2} = 25 – 16

x^{2} = 9

x = 3 cm

Area of given figure = Area of trapezium + area of rectangle

Area of given figure =

Area of given figure =

Area of given figure =

Therefore area of given figure is 54 cm^{2}

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