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Given Definite Integral can be written as: ……(1)

Let us assume y = logx

Differentiating w.r.t x on both sides

d(y) = d(logx) ……(2)

Upper limit for the Definite Integral:

x = 3 y = log(3)

y = log3……(3)

Lower limit for the Definite Integral:

x = 1 y = log(1)

y = 0……(4)

Substituting (2),(3),(4) in the eq(1) we get, We know that ∫ cos x dx = sin x + c We know that: here f’(x) is derivative of f(x))

I(x) = sin(log3) – sin(0)

I(x) = sin(log3) – 0

I(x) = sin(log3) Rate this question :

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