# Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as(i) the sum of the areas of two triangles and one rectangle.(ii) the difference of the area of a rectangle and the sum of the areas of two triangles. Area of a trapezium ABCD
= area (∆DFA) + area (rectangle DFEC) + area (∆CEB)
= (1/2 × AF × DF) + (FE × DF) + (1/2 × EB × CE)
= (1/2 × AF × h) + (FE × h) + (1/2 × EB × h)

= 1/2 × h × (AF + 2FE + EB)
= 1/2 × h × (AF + FE + EB + FE)
= 1/2 × h × (AB + FE)

= 1/2 × h × (AB + CD) [Opposite sides of rectangle are equal]

= 1/2 × 6 × (15 + 10)

= 1/2 × 6 × 25 = 75

Area of trapezium = 75 cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Quiz | Imp. Qs on Polyhedrons38 mins  Methods of Charging a Body44 mins  Area of Polygons41 mins  NCERT | Imp. Qs on Mensuration45 mins  Smart Revision | Surface Area and Volume of Cuboid50 mins  The History and Chemistry Behind a Matchstick!37 mins  Quiz | Mensuration43 mins  Quiz | Mensuration45 mins  NCERT | Surface Area of Solid Shapes39 mins  NCERT | Imp. Qs. of Mensuration53 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 