Evaluate the following Integrals:

Let

We have sin2x + cos2x = 1

Put sin2x = t

2 sin x cos x dx = dt (Differentiating both sides)

sin x cos x dx = dt

When x = 0, t = sin20 = 0

So, the new limits are 0 and 1.

Substituting this in the original integral,

Recall

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