Q. 5

# The sum of the fi

Let the three numbers be .

According to the question

…(1)

…(2)

From 2 we get

a3 = 1

a = 1.

From 1 we get

10a + 10ar + 10ar2 = 39r …(3)

Substituting a = 1 in 3 we get

10(1) + 10(1)r + 10(1)r2 = 39r

10r2 – 29r + 10 = 0

10r2 – 25r – 4r + 10 = 0…(4)

5r(2r – 5) – 2(2r – 5) = 0

r = or r =

Now the equation will be

The three numbers are.

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