Q. 455.0( 1 Vote )

Evaluate the foll

Answer :

Let


Put 1 + log x = t

Differentiating both sides, we get,

Now, changing the limits,

When x = 1, t = 1 + log 1 = 1


When x = 2, t = 1 + log 2


So, the new limits are 1 and 1 + log 2.


Substituting this in the original integral,




Recall







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