Answer :


In ΔCEF


CE = 10 cm and EF = 6cm


Using pythagorous theorem:


CE2 = CF2 + EF2


CF2 = CE2 - EF2


CF2 = 152 - 62


CF2 = 225-36


CF2 = 189


CF = 17 cm


Area of trapezium = area of parallelogram AECD + area of area of triangle CEF


Area of trapezium =


Area of trapezium =


Area of trapezium = 221 + 102 = 323 cm2


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