Q. 164.4( 14 Votes )

# The parallel side

Answer :

In ΔCEF

CE = 10 cm and EF = 6cm

Using pythagorous theorem:

CE^{2} = CF^{2} + EF^{2}

CF^{2} = CE^{2} - EF^{2}

CF^{2} = 10^{2} - 6^{2}

CF^{2} = 100-36

CF^{2} = 64

CF = 8 cm

Area of trapezium = area of parallelogram AECD + area of area of triangle CEF

Area of trapezium =

Area of trapezium =

Area of trapezium = 104 + 48 = 152 cm^{2}

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