Answer :



In ΔCEF


CE = 10 cm and EF = 6cm


Using pythagorous theorem:


CE2 = CF2 + EF2


CF2 = CE2 - EF2


CF2 = 102 - 62


CF2 = 100-36


CF2 = 64


CF = 8 cm


Area of trapezium = area of parallelogram AECD + area of area of triangle CEF


Area of trapezium =


Area of trapezium =


Area of trapezium = 104 + 48 = 152 cm2


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