# The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?

Length of square = 4 m

Area of square = side2

Area of square = 4 × 4 = 16 m2

Area of square = area of rhombus

Area of rhombus = 16 m2

Area of rhombus = 16 = Other diagonal of rhombus = 16 m

In ΔAOB Using pythagorous theorem:

AB2 = OA2 + OB2

AB2 = 82 + 12

AB2 = 65

AB = Rhombus is a parallelogram, area of parallelogram = base× altitude

Area of parallelogram = AB × DE

Area of parallelogram = × DE

DE = Altitude of Rhombus = cm

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