Q. 144.0( 5 Votes )

In a GP the 3rd term is 24, and the 6th term is 192. Find the 10th term.

Answer :

Tn = arn-1


a = a, r =?, Tn = 24 n = 3


a = a, r =?, Tn = 192 n = 6


24 = a.r3-1


24 = a.r2…(1)


192 = a.r6-1


192 = a.r5…(2)


Divide (2) by (1) we get



r3 = 8


r = 2


Substituting r in 2 we get


a = 6


T10 = 6.210-1


= 6.29


= 3072.


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