# In a GP the 3<sup

Tn = arn-1

a = a, r =?, Tn = 24 n = 3

a = a, r =?, Tn = 192 n = 6

24 = a.r3-1

24 = a.r2…(1)

192 = a.r6-1

192 = a.r5…(2)

Divide (2) by (1) we get

r3 = 8

r = 2

Substituting r in 2 we get

a = 6

T10 = 6.210-1

= 6.29

= 3072.

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