Q. 103.5( 6 Votes )

# The seventh term of a G.P. is 8 times the fourth term and 5th term is 48. Find the G.P.

Answer :

T_{n} = ar^{n-1}

In the GP, the 7th term is 8 times the 4th term. So

ar^{6} = 8ar^{3}, or

r^{3} = 8 or r = 2.

ar^{4} = 48,

a.16 = 48

a = 3

The first term is 3 and r = 2

∴ GP = 3, 6, 12, …

Rate this question :

The product of three numbers in G.P. is 216. If 2, 8, 6 be added to them, the results are in A.P. Find the numbers.

RD Sharma - MathematicsFind three number in G.P. whose sum is 38 and their product is 1728.

RD Sharma - MathematicsThe sum of the first three terms of a G.P. is , and their product is 1. Find the common ratio and the terms.

RD Sharma - MathematicsThe sum of first three terms of a G.P. is , and their product is – 1. Find the G.P.

RD Sharma - MathematicsExpress as a rational number.

RS Aggarwal - MathematicsIf a, b, c are in GP, prove that (a^{2} + b^{2}), (ab + bc), (b^{2} + c^{2}) are in GP.

Express as a rational number.

RS Aggarwal - MathematicsProve that

RS Aggarwal - MathematicsIf a, b, c are in GP, prove that a^{2}, b^{2}, c^{2} are in GP.

The sum of n terms of a progression is (2^{n} – 1). Show that it is a GP and find its common ratio.