# If x3 + x2 ‒ ax + b is divisible by (x2 ‒ x), write the values of a and b.

Firstly, equating x2 – x to 0 to find the zeros we get:

x (x – 1) = 0

x = 0 or x – 1 = 0

x = 0 or x = 1

As x3 + x2 – ax + b is divisible by x2 – x

The zeros o x2 – x will satisfy x3 + x2 – ax + b

Hence, (0)3 + 02 – a (0) + b = 0

b = 0

Also,

(1)3 + 12 – a (1) + 0 = 0

a = 2

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