# If k + 2, 4k–6, 3k–2 are the three consecutive terms of an A.P, then the value of k isA. 2B. 3C. 4D. 5

From AP, it is clear that

(4k-6)-(k + 2) = (3k-2)-(4k-6)

3k-8 = -k + 4

4k = 12 or k = 3.

So the correct choice is B.

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