Answer :

We see that the problem under consideration is a GP with a = 1 and common ratio r = sec x.

Sum of GP S =


Where n = number of terms, here n = 6.


Therefore


S =


The numerator is of the form a6-b6


a6-b6 = (a + b)(a-b)(a2 + b2 + ab)(a2 + b2-ab)


Therefore (sec x)6 -16 = (sec x + 1)(sec x-1)(sec2x + 1 + sec x)(sec2x + 1-sec x)


(sec x)6 -16 = (sec x + 1)(sec x-1)(1 + sec2x + sec4x)


S = = (sec x + 1)(1 + sec2x + sec4x)


So the correct answer is option B.

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