Q. 145.0( 1 Vote )

The sequence –3, –3, –3,… is
A. an A.P. only

B. a G.P. only

C. neither A.P. nor G.P

D. both A.P. and G.P.

Answer :

The given sequence is -3, -3, -3


Test for AP


If a,b,c…are in AP the b-a = c-b…


-3-(-3) = -3-(-3) = 0


Therefore, the series is in AP.


Test for GP


If a,b,c.. are in GP then



Therefore, the series is in GP.


The series is both in AP and GP.


So the correct option is D.

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