Q. 145.0( 1 Vote )
The sequence –3, –3, –3,… is
A. an A.P. only
B. a G.P. only
C. neither A.P. nor G.P
D. both A.P. and G.P.
The given sequence is -3, -3, -3
Test for AP
If a,b,c…are in AP the b-a = c-b…
-3-(-3) = -3-(-3) = 0
Therefore, the series is in AP.
Test for GP
If a,b,c.. are in GP then …
Therefore, the series is in GP.
The series is both in AP and GP.
So the correct option is D.
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