Q. 3 D4.0( 10 Votes )

# Factorise the following using appropriate identities.18a2 – 50

Take out common factor 2

18a2 – 50 = 2 (9a2 - 25)

Now

9a2 can be written as (3a)2

25 can be written as 52

18a2 – 50 = 2 ((3a)2 – 52)

using the identity (a + b) × (a – b) = a2 – b2

here a = 3a and b = 5

therefore 18a2 – 50 = 2 (3a + 5) (3a – 5)

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