Q. 1 L3.7( 7 Votes )

# Solve the following equation.

Given equation:

(Transposing to LHS and to

RHS)

(LCM of 8 and 16 is 16; of 7 and 14

is 14)

(Taking out 7 common in numerator of RHS)

LCM of 2 and 16 is 16.

(Multiplying by 16 on both sides)

t – 5 = 8 (t – 1)

t – 5 = 8t – 8 (Removing bracket)

t – 8t = -8 + 5 (Transposing 8t to LHS and 5 to RHS)

-7t = -3

t = (Transposing -7 to RHS)

t =

The solution of the given equation is t = .

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