Q. 114.1( 204 Votes )

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Answer :

27x3 + y3 + z3 – 9xyz = (3x)3 + y3 + z3 – 3 × 3xyz

Using identity,


x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – xz)


27x3 + y3 + z3 – 9xyz


= (3x + y + z) {(3x)2 + y2 + z2 – 3xy – yz – 3xz}


= (3x + y + z) (9x2 + y2 + z2 – 3xy – yz – 3xz)

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