# Find the sum of f

First term = a

Common difference = d

3rd term = a + (3–1)d = a + 2d

7th term = a + (7–1)d = a + 6d

Now, 3rd term = 7

a + 2d = 7 ………………………(1)

And, 7th term = 3 × (3rd term) + 2

a + 6d = 3(a + 2d) + 2

a + 6d = 3a + 6d + 2

2a = –2

a = –1

Putting value of a in (1)

( –1) + 2d = 7

2d = 8

d = 4

Sum of terms = Sum of terms = Sum of terms = Sum of terms = 740

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