Q. 9

Find p(0), p(1),𝑝(βˆ’2) for the following polynomials:

(i) (π‘₯)=10π‘₯βˆ’4π‘₯2 –3

(ii) (𝑦)=(y + 2) (y – 2)

Answer :

(i) given p(x) = 10π‘₯βˆ’4π‘₯2 –3


∴ p (0) = 10 Γ— 0 – 4 Γ— 0 – 3 = – 3


P (1) = 10 Γ— 1 – 4 Γ— 1 – 3 = 3


P ( – 2) = 10 Γ— – 2 – 4 Γ— ( – 2)2 – 3 = – 39


The value of the polynomial (π‘₯) = 10π‘₯βˆ’4π‘₯2 –3 at p(0) , p(1) and p


( – 2) is – 3, 3 and – 39 respectively.


(ii) Given polynomial is p (y) = (y + 2) (y – 2)


= y2 – 4


Now p (0) = 02 – 4 = – 4


P (1) = 12 – 4 = – 3


P ( – 2) = ( – 2)2 – 4 = 0


Hence the value of the given polynomial at p(0) , p(1) and p


( – 2) is – 4, – 3 and 0.


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