Q. 9

# Find p(0), p(1),𝑝(−2) for the following polynomials:(i) (𝑥)=10𝑥−4𝑥2 –3(ii) (𝑦)=(y + 2) (y – 2)

(i) given p(x) = 10𝑥−4𝑥2 –3

p (0) = 10 × 0 – 4 × 0 – 3 = – 3

P (1) = 10 × 1 – 4 × 1 – 3 = 3

P ( – 2) = 10 × – 2 – 4 × ( – 2)2 – 3 = – 39

The value of the polynomial (𝑥) = 10𝑥−4𝑥2 –3 at p(0) , p(1) and p

( – 2) is – 3, 3 and – 39 respectively.

(ii) Given polynomial is p (y) = (y + 2) (y – 2)

= y2 – 4

Now p (0) = 02 – 4 = – 4

P (1) = 12 – 4 = – 3

P ( – 2) = ( – 2)2 – 4 = 0

Hence the value of the given polynomial at p(0) , p(1) and p

( – 2) is – 4, – 3 and 0.

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