Q. 9

# Find p(0), p(1),π(β2) for the following polynomials:(i) (π₯)=10π₯β4π₯2 β3(ii) (π¦)=(y + 2) (y β 2)

(i) given p(x) = 10π₯β4π₯2 β3

β΄ p (0) = 10 Γ 0 β 4 Γ 0 β 3 = β 3

P (1) = 10 Γ 1 β 4 Γ 1 β 3 = 3

P ( β 2) = 10 Γ β 2 β 4 Γ ( β 2)2 β 3 = β 39

The value of the polynomial (π₯) = 10π₯β4π₯2 β3 at p(0) , p(1) and p

( β 2) is β 3, 3 and β 39 respectively.

(ii) Given polynomial is p (y) = (y + 2) (y β 2)

= y2 β 4

Now p (0) = 02 β 4 = β 4

P (1) = 12 β 4 = β 3

P ( β 2) = ( β 2)2 β 4 = 0

Hence the value of the given polynomial at p(0) , p(1) and p

( β 2) is β 4, β 3 and 0.

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