Q. 74.5( 2 Votes )

In the arithmetic sequence 60, 56, 52, 48,…, starting from the first term, how many terms are needed so that their sum is 368?

Answer :

In the A.P.


First term = 60


Common difference = 56 – 60 = –4


Sum of terms =


368 =


368 =


736 = n (124 – 4n)


4n2 – 124n + 736 = 0


4n2 – 92n–32n + 736 = 0


4n(n–23) –32(n–23) = 0


(4n–32)(n–23) = 0


4n = 32 or n = 23


n = 8 or n = 23


Therefore, no. of terms can be 8 or 23


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