# In an arithmetic series, the sum of first 11 terms is 44 and that of the next 11 terms is 55. Find the arithmetic series.

Sum of terms = 44 = 8 = 2a + 10d

2a + 10d = 8 ……………………….(1)

Now sum of next 11 terms is 55

Sum of first 22 terms = Sum of first 11 terms + Sum of next 11 terms

Sum of first 22 terms = 44 + 55 = 99

Sum of terms = 99 = 9 = 2a + 21d

2a + 21d = 9 ……….(1)

Subtracting (1) from (2), we get

11d = 1

d = 1/11

Putting value of d in (1), we get

2a + 10(1/11) = 8

2a = 8–(10/11)

2a = 78/11

a = 39/11

Therefore, the series is Rate this question :

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