Q. 63.7( 3 Votes )

In an arithmetic series, the sum of first 11 terms is 44 and that of the next 11 terms is 55. Find the arithmetic series.

Answer :

Sum of terms =


44 =


8 = 2a + 10d


2a + 10d = 8 ……………………….(1)


Now sum of next 11 terms is 55


Sum of first 22 terms = Sum of first 11 terms + Sum of next 11 terms


Sum of first 22 terms = 44 + 55 = 99


Sum of terms =


99 =


9 = 2a + 21d


2a + 21d = 9 ……….(1)


Subtracting (1) from (2), we get


11d = 1


d = 1/11


Putting value of d in (1), we get


2a + 10(1/11) = 8


2a = 8–(10/11)


2a = 78/11


a = 39/11


Therefore, the series is


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