One of the two di

Let the digit at ten’s place and one’s place be x and 3x.

Then original number =10(x) + 1(3x) = 13x

On interchanging the digits, the digits at ones place and tens place will be x and 3x

The number formed after interchanging = 10(3x) + x = 31x

Now, New Number + Original Number = 88

13x + 31x = 88

44x = 88

We get, x = 2

Thus, the two digit number is 13x = 13(2) = 26 or 62.